Resistors R_(1)=50\Omega and R_(2)=10\Omega and an ideal ammeter are connected as shown in the figure. The potential difference between points A and B is U=100V. What value does read the ammeter? 12.0V4.00\Omega

Question

Anu Bhardwaj · Accepted Answer

Problem restatement

$R_1 = 50 \, \Omega$ , $R_2 = 10 \, \Omega$ .
Potential difference between $A$ and $B$ is $U = 100 \, V$ .
An ideal ammeter is connected between the midpoints $C$ and $D$ of two resistor branches.
Question: What does the ammeter read?

Step 1: Understand circuit structure

The circuit is a Wheatstone bridge:

Left branch: two resistors $R_1$ (top) and $R_2$ (bottom).
Right branch: two resistors $R_2$ (top) and $R_1$

Physics

Physics

Anu Bhardwaj

Answer

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