' Write a Python program to solve the popular "Hashiwokakero" or…

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'  Write a Python program to solve the popular "Hashiwokakero" or…

Manu · Accepted Answer

Step 1: Parse the Input and Identify Islands First, we'll write a function to parse the input data and identify the islands and their values. We'll represent each island as an object with its coordinates and value. class Island: def __init__(self, x, y, value): self.x = x self.y = y self.value = value self.connections = [] def __repr__(self): return f"Island({self.x}, {self.y}, {self.value})" def parse_input(input_data): islands = [] for y, row in enumerate(input_data): for x, cell in enumerate(row): if cell.isdigit() or cell in 'abc': value = int(cell, 16) islands.append(Island(x, y, value)) return islands # Example input data input_data = [ ".1.....6....7....", "....4.4.2....4.2.", "2....3.8....6.2..", "........2........", ".....5.c.7.a.a...", "5.6...8.5........", ".................", "........5..9.a..8", ".b.8.4.4.5.......", ".................", "...3..2..4.1.5...", "2....2.7.4...7.2.", "5....3..........", "....4..3.1.2....." ] islands = parse_input(input_data) for island in islands: print(island) Step 2: Solve the Puzzle and Print the Solution Next, we'll write functions to solve the puzzle by connecting islands with bridges and then print the solution. class Bridge: def __init__(self, island1, island2): self.island1 = island1 self.island2 = island2 self.count = 1 def __repr__(self): return f"Bridge({self.island1}, {self.island2}, {self.count})" def is_valid_bridge(island1, island2, bridges): if island1.x == island2.x: for y in range(min(island1.y, island2.y) + 1, max(island1.y, island2.y)): if any(b.island1.x == island1.x and b.island1.y == y for b in bridges): return False elif island1.y == island2.y: for x in range(min(island1.x, island2.x) + 1, max(island1.x, island2.x)): if any(b.island1.y == island1.y and b.island1.x == x for b in bridges): return False return True def add_bridge(island1, island2, bridges): for bridge in bridges: if (bridge.island1 == island1 and bridge.island2 == island2) or (bridge.island1 == island2 and bridge.island2 == island1): bridge.count += 1 return bridges.append(Bridge(island1, island2)) def solve(islands): bridges = [] for island in islands: for other_island in islands: if island == other_island: continue if (island.x == other_island.x or island.y == other_island.y) and is_valid_bridge(island, other_island, bridges): while len(island.connections) < island.value and len(other_island.connections) < other_island.value: add_bridge(island, other_island, bridges) island.connections.append(other_island) other_island.connections.append(island) return bridges def print_solution(input_data, bridges): solution = [list(row) for row in input_data] for bridge in bridges: if bridge.island1.x == bridge.island2.x: for y in range(min(bridge.island1.y, bridge.island2.y) + 1, max(bridge.island1.y, bridge.island2.y)): solution[y][bridge.island1.x] = '|' if bridge.count == 1 else '"' if bridge.count == 2 else '#' elif bridge.island1.y == bridge.island2.y: for x in range(min(bridge.island1.x, bridge.island2.x) + 1, max(bridge.island1.x, bridge.island2.x)): solution[bridge.island1.y][x] = '-' if bridge.count == 1 else '=' if bridge.count == 2 else 'E' for row in solution: print(''.join(row)) # Solving the puzzle and printing the solution bridges = solve(islands) print_solution(input_data, bridges) Full Program Combining both steps, the complete program looks like this: class Island: def __init__(self, x, y, value): self.x = x self.y = y self.value = value self.connections = [] def __repr__(self): return f"Island({self.x}, {self.y}, {self.value})" class Bridge: def __init__(self, island1, island2): self.island1 = island1 self.island2 = island2 self.count = 1 def __repr__(self): return f"Bridge({self.island1}, {self.island2}, {self.count})" def parse_input(input_data): islands = [] for y, row in enumerate(input_data): for x, cell in enumerate(row): if cell.isdigit() or cell in 'abc': value = int(cell, 16) islands.append(Island(x, y, value)) return islands def is_valid_bridge(island1, island2, bridges): if island1.x == island2.x: for y in range(min(island1.y, island2.y) + 1, max(island1.y, island2.y)): if any(b.island1.x == island1.x and b.island1.y == y for b in bridges): return False elif island1.y == island2.y: for x in range(min(island1.x, island2.x) + 1, max(island1.x, island2.x)): if any(b.island1.y == island1.y and b.island1.x == x for b in bridges): return False return True def add_bridge(island1, island2, bridges): for bridge in bridges: if (bridge.island1 == island1 and bridge.island2 == island2) or (bridge.island1 == island2 and bridge.island2 == island1): bridge.count += 1 return bridges.append(Bridge(island1, island2)) def solve(islands): bridges = [] for island in islands: for other_island in islands: if island == other_island: continue if (island.x == other_island.x or island.y == other_island.y) and is_valid_bridge(island, other_island, bridges): while len(island.connections) < island.value and len(other_island.connections) < other_island.value: add_bridge(island, oth

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