' \ufeff 2 A king has ordered all n women in his kingdom to stand…

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Step 1: Understand the Problem We need to find the optimal position of a queen in a line of women such that the number of women who need to change direction is minimized. Women are represented by a string k where 'R' means facing right and 'L' means facing left. Explanation: Input Reading: Read the number of women and their facing directions. Step 2: Define the Input and Output Input: An integer n representing the number of women. A string k of length n where each character is either 'R' or 'L'. Output: The position (1-based index) of the queen that causes the least number of direction changes. The minimum number of women who need to change direction. Explanation: Initialization: Set initial values for minimum changes and the best queen position. Step 3: Plan the Approach Initialize Variables: min_changes to keep track of the minimum number of direction changes (initialized to n because the worst case is all women need to change). best_position to store the position of the queen that results in the minimum changes. Iterate Over Each Woman: For each woman, count the number of women who would need to change direction if she is chosen as the queen. Women to the left of the chosen queen who are facing 'R' need to turn to face 'L'. Women to the right of the chosen queen who are facing 'L' need to turn to face 'R'. Update the Best Position: Track the position that results in the fewest changes. Explanation: Iterate Over Positions: Loop through each potential queen position. Count Changes Left: Count the 'R' on the left of the current position who need to turn. Count Changes Right: Count the 'L' on the right of the current position who need to turn. Update Best Position: If the current position results in fewer changes, update the best position and minimum changes. Step 4: Implement the Solution Here's the code with comments to illustrate each step: #include #include #include using namespace std; int main() { int n; cin >> n; // Read the number of women string k; cin >> k; // Read the string depicting directions // Initialize variables to track the best queen position and minimum changes int min_changes = n; // Start with the worst case (maximum possible changes) int best_position = 1; // Start with the first position (1-based index) // Iterate over each possible queen position for (int i = 0; i < n; ++i) { int changes = 0; // Count the 'R's to the left of the current position for (int j = 0; j < i; ++j) { if (k[j] == 'R') { ++changes; } } // Count the 'L's to the right of the current position for (int j = i + 1; j < n; ++j) { if (k[j] == 'L') { ++changes; } } // Update the best position if the current one has fewer changes if (changes < min_changes) { min_changes = changes; best_position = i + 1; // 1-based index } } // Output the result cout << best_position << " " << min_changes << endl; return 0; } Output: Step-by-Step Calculation For Position 1 (0-based index 0): Left: None Right: RLRLL Changes needed: 0 ('R' -> 'L') + 3 ('L' -> 'R') = 3 changes For Position 2 (0-based index 1): Left: R Right: LRLL Changes needed: 1 ('R' -> 'L') + 2 ('L' -> 'R') = 3 changes For Position 3 (0-based index 2): Left: RL Right: RLL Changes needed: 1 ('R' -> 'L') + 2 ('L' -> 'R') = 3 changes For Position 4 (0-based index 3): Left: RLR Right: LL Changes needed: 2 ('R' -> 'L') + 1 ('L' -> 'R') = 3 changes For Position 5 (0-based index 4): Left: RLRL Right: L Changes needed: 2 ('R' -> 'L') + 1 ('L' -> 'R') = 3 changes Explanation: Output Result: Print the best queen position and the minimum number of direction changes. Conclusion The optimal queen is at position 6 (1-based index) with 2 changes. 5 2

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